What is the minimum force ?

2Blocks01

What is the minimum force F must be applied to lift the body mass m? The height of the inclined plane is equal to H and the length of the inclined plane is equal to L. Consider the blocks to be weightless and neglect friction.


Solution. Posted on Saturday, December 27, 2014.

If a movable pulley moved a distance l than the force F performed work equal to F*l. The body on the inclined plane at the same time moved a distance 2*l and rose to a height of h. The amount of gravitational potential energy (m*g*h) possessed by an elevated the body is equal to the work done. Thereby, m*g*h=F*l. The h could be found from the similarity of triangles.
h = 2*l*H/L
Now, when looking at the previous equation, it can be written as m*g*2*l*H/L=F*l
Finally,
F=2*m*g*H/L

Advertisements

3 thoughts on “What is the minimum force ?

  1. First find the angle, theta, between the plane
    and floor.

    theta = arcsin(H/L)

    The force, f, against the rope parallel
    to the incline is

    f = m*g*cos(theta)

    which is the force needed to lift it up
    the incline. The pulley at the end of the
    incline doesn’t multiply the force f, it
    just transmits it to one side of the other
    pulley.

    The minimum force, F, to lift the mass, m,
    is twice the two forces pulling up of the
    pulley pulling down. The two forces lifting
    up are equal to f.

    F = 2*m*g*cos(theta).

    It’s hard to answer this problem with mostly
    words, but fun.

    Like

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s