A barometer shows that an air pressure inside of a rocket before the launch is 10^5 pa. What is the change of air temperature inside the rocket during its launch, if the air pressure is increased to 1.2*10^5 pa ?
The rocket accelerates at a rate of 10 m/s^2.
The process inside of the rocket is an isochoric process because a volume of the air inside is constant.
The equation of the isochoric process is
P1/T1=P2/T2 , where P1 is the initial pressure, P2 is the final pressure, T1 is the initial temperature and T2 is the final temperature.
1×10^5 / T1 = 1.2×10^5 / T2
T2 / T1 = 1.2
Finally, the air temperature is increased 1.2 times.