An Empire starship fires at Skywalker’s ship

star-wars.jpg

An Empire starship fires a beam of electrons at Skywalker’s ship. Each electron has an initial kinetic energy of 1.6×10−17 J. The Skywalker’s ship has been fitted out with the electrostatic shield technology for defense against electron beam weapons. The electric field of the shield points directly inward. If the electrons stop after travelling 83 m, what is the size of the electric field generated by the ship’s shield? Please ignore relativistic effects.

Solution.

The electron stops after travelling 83 m. It is meant that electron has lost all of its kinetic energy. The kinetic energy spent on work done against the electric force. We can write it as

Ek = W

The work is defined as:

W = F*x*cosθ

where is the displacement the object was moved, F is the force by which it was moved and θ is the angle between force and the displacement.

θ = 0, thus

W = F*x.

Also, the electric field E is given by

E = F/q or F = q*E

where q, in our case, is the charge on an electron 1.60×10−19 C.

Thus,

Ek = W = F*x = q*E*x

and finally,

E = Ek / (q*x) = 1.6×10−17 / (1.60×10−19 * 83)  = 1.2 V/m.

 

 

Advertisements

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s